Unit of latent heat of fusion is :

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J/Kg

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J/K

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J/Kg-K

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Solution

The correct option is B J/Kg
Latent heat of fusion $= \frac{H e a t r e q u i r e d t o c h a n g e s o l i d i n t o l i q u i d}{m a s s}$
Unit of latent heat of fusion $= J / K g$

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Similar questions

Heat energy required to melt $10 k g$ ice at its melting point will be _____. (The latent heat of fusion of water = $333.55 k J k g^{- 1}$ ).

Q. Calculate the quantity of heat required to convert 10 kg of ice at

0^{\circ} C

into water at the same temperature.
(Latent heat of fusion of ice

- 335 \times 10^{3} J / k g

)

Q. Calculate the amount of heat required to vapourise

2 k g

of water at

100^{\circ} C

, for which the latent heat of vapourisation is

2260 k J / k g

The graph shown in the figure represents change in the temperature of $5 k g$ of a substance with time, as it absorbs heat at a constant rate of $42 k J$ $m i n^{- 1}$ . The latent heat of vapourization of the substance is:

Q. Determine the heat required to convert

3 k g

of ice from

- 7^{\circ} C

40^{\circ} C

. Latent heat of ice =

334.7 J / k g K

, specific heat of ice =

2108 J / k g K

and specific heat of water =

4186 J / k g K

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Unit of latent heat of fusion is :

The correct option is B J/KgLatent heat of fusion =HeatrequiredtochangesolidintoliquidmassUnit of latent heat of fusion =J/Kg

The correct option is B J/Kg
Latent heat of fusion $= \frac{H e a t r e q u i r e d t o c h a n g e s o l i d i n t o l i q u i d}{m a s s}$
Unit of latent heat of fusion $= J / K g$