Upon adding a number and its reverse, the result obtained is divisible by
Let the number be ab, i.e. 10a + b.
The reverse would be ba, i.e. 10b + a
Addition = 10 a + b + 10b + a = 11a + 11b = 11(a + b)
which has a multiple 11, so addition of a number and its reverse is always divisible by 11.