Upon electrolysis of 2 litres of pure water, litre(s) of $O_{2}$ gas is/are liberated.

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Solution

The correct option is A 1
The equation for the electrolysis of water is:

$2 H_{2} O (l) \to 2 H_{2} (g) + O_{2} (g)$

Thus, upon electrolysis of two litres of water, one litre of oxygen gas is liberated.

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