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Byju's Answer

Standard XII

Chemistry

Oxyacids of Phosphorus

Upon heating ...

Question

Upon heating $K C l O_{3}$ in the presence of catalytic amount of $M n O_{2}$ , a gas W is formed. Excess amount of W reacts with white phosphorus to give X. The reaction of X with $H N O_{3}$ gives Y and Z.

Y and Z are, respectively

N_{2} O_{3}

and

H_{3} P O_{4}

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N_{2} O_{5}

and

H P O_{3}

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N_{2} O_{4}

and

H P O_{3}

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N_{2} O_{4}

and

H_{3} P O_{3}

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Solution

The correct option is B $N_{2} O_{5}$ and $H P O_{3}$
$2 K C l O_{3} M n O_{2} - --- \to 2 K C l + 3 O_{2} W$

$P_{4} + 5 O_{2} \to P_{4} O_{10}$
x

$P_{4} O_{10} + 4 H N O_{3} \to 4 H P O_{3} + 2 N_{2} O_{5}$

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Similar questions

Q. Upon heating

K C l O_{3}

in the presence of catalytic amount of

M n O_{2}

, a gas W is formed. Excess amount of W reacts with white phosphorus to give X. The reaction of X with

H N O_{3}

gives Y and Z.

Y and Z are, respectively

Q. A compound

(x)

on treatment with

N a

gives

(y)

, and with

P C l_{5}

gives

(z)

(y)

and

(z)

react together to form diethyl ether.

(x), (y)

and

(z)

respectively are:

The reactions of $C l_{2}$ gas with cold-dilute and hot-concentrated NaOH in water give sodium salts of two different oxoacids of chlorine, P and Q, respectively. The $C l_{2}$ gas reacts with $S O_{2}$ gas, in presence of charcoal, to give a product R reacts with white phosphorus to give a compound S. On hydrolysis, S gives an oxoacid of phosphorus.

3. P and Q, respectively, are the sodium salts of

Q. A white solid X on heating gives a white solid Y and an acidic gas Z. Gas Z is also given out when X reacts with an acid. The compound Y is also formed if caustic soda is left open in the atmosphere. X, Y and Z are :

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Upon heating KClO3 in the presence of catalytic amount of MnO2, a gas W is formed. Excess amount of W reacts with white phosphorus to give X. The reaction of X with HNO3 gives Y and Z. Y and Z are, respectively

The correct option is B N2O5 and HPO32KClO3MnO2−−−−→2KCl+3O2W P4+5O2→P4O10 x P4O10+4HNO3→4HPO3+2N2O5

Upon heating $K C l O_{3}$ in the presence of catalytic amount of $M n O_{2}$ , a gas W is formed. Excess amount of W reacts with white phosphorus to give X. The reaction of X with $H N O_{3}$ gives Y and Z.

Y and Z are, respectively

The correct option is B $N_{2} O_{5}$ and $H P O_{3}$
$2 K C l O_{3} M n O_{2} - --- \to 2 K C l + 3 O_{2} W$

$P_{4} + 5 O_{2} \to P_{4} O_{10}$
x

$P_{4} O_{10} + 4 H N O_{3} \to 4 H P O_{3} + 2 N_{2} O_{5}$