Upon treatment with $A l (O E t)_{3}$ followed by usual reactions (work up), $C H_{3} C H O$ will produce:

only

C H_{3} C O O C H_{2} C H_{3}

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A mixture of

C H_{3} C O O H

and

E t O H

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Only

C H_{3} C O O H

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Only

E t O H

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Solution

The correct option is A only $C H_{3} C O O C H_{2} C H_{3}$

The Tishchenko Reaction is a disproportionation reaction that allows the preparation of esters from two equivalents of an aldehyde.Catalysts are aluminium alkoxides or sodium alkoxides.

$C H_{3} C H O$ on treatment with aluminium alkoxide gives ester $C H_{3} C O O C H_{2} C H_{3}$ only as it undergoes Tischenko reaction.

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