Use a method of your own choice to find the H.C.F. of the following:
(iv) $24, 36, 60 and 132$

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Solution

(iv) Factor of a number: The number by which the given number can be divided completely
Prime factors of $24 = 2 \times 2 \times 2 \times 3$
Prime factors of $36 = 2 \times 2 \times 3 \times 3$
Prime factors of $60 = 2 \times 2 \times 3 \times 5$
Prime factors of $132 = 2 \times 2 \times 3 \times 11$
$∴$ Common prime factors of 24, 36, 60 and $132 = 2 \times 2 \times 3$
Hence, H.C.F. of 24, 36, 60 and $132 = 2 \times 2 \times 3 = 12$

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Use a method of your own choice to find the H.C.F. of the following: (iv) 24,36,60 and 132

Use a method of your own choice to find the H.C.F. of the following:
(iv) $24, 36, 60 and 132$