Use a suitable identity to get following products.
$(a^{2} + b^{2}) (b^{2} - a^{2})$

b^{2} - a^{4}

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b^{4} - a^{7}

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b^{5} - a^{4}

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b^{4} - a^{4}

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Solution

The correct option is D $b^{4} - a^{4}$
$(a^{2} + b^{2}) (- a^{2} + b^{2})$
Using,
$(a + b) (a - b) = a^{2} - b^{2}$
$= (b^{2} + a^{2}) (b^{2} - a^{2})$
$= b^{4} - a^{4}$

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If X = 1 - a^{2} and Y = 1 - b^{2}, then what is X^{2} + Y^{2} ?

Question 92 (xviii)

Factorise the following using the identity $a^{2} - b^{2} = (a + b) (a - b) .$

$a^{4} - (a - b)^{4}$

a^{4} b - a b^{4}, a^{4} b^{2} - a^{2} b^{4}

a^{2} b^{2} (a^{4} - b^{4})

a^{4} - b^{4} + {2 b}^{2} - 1

(a^{2} - b^{2}) + \frac{a^{4} - b^{4}}{2!} + \frac{a^{6} - b^{6}}{3!} + . . .

\infty

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