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Question

Use identities to evaluate 2012


A

40401

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B

40411

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C

41401

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D

40141

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Solution

The correct option is A

40401


Use the identity (a+b)2 = a2 + b2 + 2ab

201 = 200 + 1

Substituting 200 and 1 in the places of a and b respectively,

. (200+1)2 = 2002 + 12 + (2×200×1)

= 40000 + 1 + 400

= 40401


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