Question

Use Kirchhoff's rules to determine the potential difference between the points A and D when no current flows in the arm BE of the electric network shown in the figure.

Answer 1

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According to Kirchhoff's junction law at B,

$i_3=i_1+i_2$

As $i_2=0$ (given)

$\therefore i_3=i_1$

Applying second law to loop AFEB,

$\therefore i_3\times 2+i_3\times 3+i_2{R}_1=1+3+6$

$i_3=i_1=2A$

The potenital difference between A to D along the branch AFD,

$\therefore V_{AD}=2i_3-1+3\times i_3$
$=(4-1+6)V$
$=9V$