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B
540
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C
120
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D
468
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Solution
The correct option is B540 93+(−5)3+(−4)3 We know that a3+b3+c3−3abc=(a+b+c)(a2+b2+c2−ab−ac−bc) If (a+b+c)=0, then. a3+b3+c3=3abc Here, a=9 b=−5 c=−4 and a+b+c=9−5−4=0 Thus, 93+(−5)3+(−4)3 =3(9)(−5)(−4) =540