wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Use the formula to expand:

(1) (p + 5)3

Open in App
Solution

We know that (x + y)3 = x3 + 3x2y + 3xy2 + y3 .
Comparing (p + 5)3 with (x + y)3 , we get:
x = p and y = 5
Substituting these in the above formula:
(p + 5)3 = p3 + 3 × p2 × 5 + 3 × p ×52 + 53
= p3 + 15p2 + 75p + 125

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
x^2 - y^2
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon