Use the given bond enthalpy data to estimate the - H kJ for the following reaction- C - H - 414 kJ- H - Cl - 431 kJ- Cl - Cl - 243 kJ- C - Cl - 331 kJ - C H 4 g - 4 Cl 2 g - C Cl 4 g - 4HCl g

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Hess' Law

Use the given...

Question

Use the given bond enthalpy data to estimate the $Δ H (k J)$ for the following reaction.
$(C - H = 414 k J, H - C l = 431 k J, C l - C l = 243 k J, C - C l = 331 k J)$ .
$C H_{4} (g) + 4 {C l}_{2} (g) ⟶ C {C l}_{4} (g) + 4 H C l (g)$

620

No worries! We‘ve got your back. Try BYJU‘S free classes today!

330

No worries! We‘ve got your back. Try BYJU‘S free classes today!

420

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

105

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D 420
The enthalpy change for the combustion reaction is the difference between the total bond enthalpy of reactants and the total bond enthalpy of products.

$Δ H_{r} = [4 Δ H_{C - H} + 4 Δ H_{C l - C l} - 4 Δ H_{C - C l} - 4 Δ H_{H - C l}]$

Substittue values in the above expression.

$Δ H_{r} = [4 \times 414 + 4 \times 243 - 4 \times 331 - 4 \times 431]$

$Δ H_{r} = - 420 k J$

Suggest Corrections

Similar questions

Q. Given the following bond energies,

C - H = 414 K J / m o l

C - C l = 150 K J / m o l

C l - C l = 243 K J / m o l

H - C l = 432 K J / m o l

How much energy would be required in the reaction?

{C H}_{4 (g)} + {2 C l}_{2 (g)} \to {C H}_{2} {C l}_{2 (g)} + {2 H C l}_{(g)}

Q. Calculate

C - C l

bond enthalpy from following reaction :

C H_{3} C l (g) + {C l}_{2} (g) ⟶ C H_{2} {C l}_{2} (g) + H C l (g)

Δ H^{o} = - 104 k J

. If

C - H

C l - C l

and

H - C l

bond enthalpies are

414

243

and

431 k J {m o l}^{- 1}

respectively.

Q. The reaction

C H_{4} (g) + C l_{2} \to C H_{3} C l (g) + H C l (g)

has

δ H = - 25 k c a l .

From the data given below, what is the bond enthalpy of

C l - C l

bond?

Bond	Bond Energy (kcal)
$C - C$	$84$
$C - C l$	$81$
$C - H$	$x$
$C l - C l$	$y$
$H - C l$	$103$

Given:

x : y = 9 : 5

Q. Calculate the bond energy of

C l - C l

bond from the following data:

C H_{4 (g)} + C l_{(g)} \to C H_{3} C l_{(g)} + H C l_{(g)}; Δ H = - 100.3 k J

. Also the bond enthalpies of

C - H, C - C l, H - C l

bonds are

413, 326

and

431

k J m o l^{- 1}

respectively.

Q. The following reaction has

Δ H

- 25 k c a l

C H_{4} (g) + C l_{2} (g) \to C H_{3} C l (g) + H C l (g)

Bond	Bond Energy kCal
$ε_{C - C l}$	84
$ε_{H - C l}$	109
$ε_{C - H}$	$x$
$ε_{C l - C l}$	$y$
$x : y = 9 : 5$

From the given data, what is the bond enthalpy of

C l - C l

bond?

Join BYJU'S Learning Program

Use the given bond enthalpy data to estimate the ΔH(kJ) for the following reaction. (C−H=414kJ,H−Cl=431kJ,Cl−Cl=243kJ,C−Cl=331kJ). CH4(g)+4Cl2(g)⟶CCl4(g)+4HCl(g)

Use the given bond enthalpy data to estimate the $Δ H (k J)$ for the following reaction.
$(C - H = 414 k J, H - C l = 431 k J, C l - C l = 243 k J, C - C l = 331 k J)$ .
$C H_{4} (g) + 4 {C l}_{2} (g) ⟶ C {C l}_{4} (g) + 4 H C l (g)$