Question

Use the VSEPR model match the following:

Answer 1

${{ClO}^{-}}_4$ has 4 bond pairs. Hybridisation is $s{p}^3$. Hence tetrahedral.
${I^{-}}_3$ has 2 bond pairs and 3 lone pairs, Hybridisation is $sp$. Hence linear.
${{XeF}^{}}_4$ has 4 bond pairs and 2 lone pairs. Hybridisation is $s{p}^3{d}^2$. Shape is planar.
${{OSF}^{}}_2$ has 3 bond pairs and 1 lone pair. Hybridisation is $s{p}^3$. hence shape is pyramidal.
${{O_{2}SF}^{}}_2$ has 4 bond pairs. Hence tetrahedral.