Using a suitable algebraic identity- find 41 - 43-

The correct option is A 1763We know that, nbsp; 41 × 43 can be written as (40 + 1) × (40 +3) So, using the algebraic identity, nbsp;(x + a) × (x +b)= x^2 + ...

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Factorization of ax^2+bx+c

Using a suita...

Question

Using a suitable algebraic identity, find $41 \times 43$ .
1763

Open in App

Solution

The correct option is A 1763
We know that,
$41 \times 43$ can be written as $(40 + 1) \times (40 + 3)$
So, using the algebraic identity, $(x + a) \times (x + b) = x^{2} + (a + b) x + a b$

Here, $x = 40, a = 1, b = 3$
$(40 + 1) \times (40 + 3) = 40^{2} + (1 + 3) \times 40 + 1 \times 3$
$= 1600 + 160 + 3$
$= 1763$

Suggest Corrections

Similar questions

Q. Find

21 \times 23

, using a suitable algebraic identity.

Q. Find the value of

\frac{43^{3} + 47^{3}}{43^{2} - 43 \times 47 + 47^{2}}

using a suitable algebraic identity.

Q. Using the algebraic identity, evaluate 41 x 41 .

Q. Find the value of

102^{2}

using a suitable algebraic identity.

Q. Find the value of

{4.9}^{2}

using a suitable algebraic identity.

Join BYJU'S Learning Program

Using a suitable algebraic identity, find 41×43. 1763

The correct option is A 1763We know that, 41×43 can be written as (40+1)×(40+3) So, using the algebraic identity, (x+a)×(x+b)=x2+(a+b)x+ab Here, x=40,a=1,b=3 (40+1)×(40+3)=402+(1+3)×40+1×3 =1600+160+3 =1763

Using a suitable algebraic identity, find $41 \times 43$ .
1763