Using a suitable algebraic identity, the value of 1013 is ___ .
Using algebraic identity (a+b)3 = (a3+b3+3a2b+3ab2)
101 = (100+1)3 = (100)3 + (1)3 + 3×1002×1 + 3×100×12
= 1000000 + 1 +30000 + 300
=1030301