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Byju's Answer
Standard VIII
Mathematics
Algebraic Identities
Using an iden...
Question
Using an identity, evaluate
297
×
303.
A
90001
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B
89998
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C
90008
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D
89991
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Solution
The correct option is
D
89991
To evaluate : 297
×
303
297 = 300 - 3
303 = 300+ 3
Using the identity,
(
a
−
b
)
(
a
+
b
)
=
a
2
−
b
2
Hence,
297
×
303
=
(
300
−
3
)
(
300
+
3
)
=
300
2
−
3
2
=
90000
−
9
=
89991
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