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Question

Using binomial theorem, evaluate each of the following:
(102)5

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Solution

(102)5(102)5=(100+2)5=5C0(100)520+5C1(100)421+5C2100322+5C3100223+5C41001246+5C5100025=1005+5(100)4×2+10(100)34+10(100)28+5(100)16+32=1010+100+4×109+8×105+8×103+32=11040808032

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