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Question

Using elementary transformations, find the inverse of matrix [2612], if it exists.


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Solution

Let A=[2612]
We know that A=IA
[2612]=[1001]A
Applying R1R1R2
[216(2)12]=[100101]A
[1412]=[1101]A
Applying R2R2R1
[14112(4)]=[11011(1)]A
[1402]=[1112]A
Applying R212R2
[1401]=11121A
Applying R1R1+4R2
[1+4(0)4+4(1)01]=⎢ ⎢ ⎢1+4(12)1+4(1)121⎥ ⎥ ⎥A
[1001]=13121A
I=13121A
This is similar to I=A1A
Thus, A1=13121

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