Question

Using factor theorem the factors of $y^3-2y^2-y+2$ is

• A. (y - 2)(y + 1)(y - 1)
• B. (y + 2)(y + 1)(y - 1)
• C. (y - 2)(y + 2)(y - 1)
• D. (y - 2)(y + 2)(y + 1)

Answer 1

The correct option is A

(y - 2)(y + 1)(y - 1)

When $y^3-2y^2-y+2$ is divided by $y-1$, the quotient will be $y^2-y-2$.

$\therefore y^3-2y^2-y+2=(y-1)(y^2-y-2)$

= $(y-1)(y+1)(y-2)$