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Question
Using identities,evaluate.71*71
Using identities,evaluate.71*71
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Solution
The identity use here is : (a + b)² = a² + 2ab + b²
1) 71²
= (70+1)²
= 70²+ 2×70×1+ 1² [(a + b)² = a² + 2ab + b² ]
= 4900 + 140 +1
= 5041
The identity use here is : (a + b)² = a² + 2ab + b²
1) 71²
= (70+1)²
= 70²+ 2×70×1+ 1² [(a + b)² = a² + 2ab + b² ]
= 4900 + 140 +1
= 5041
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