Using identities, find the value of $72^{2} - 18^{2}$ .

Open in App

Solution

$72^{2} - 18^{2}$

We know that

$a^{2} - b^{2} = (a + b) (a - b)$

$a = 72$ $b = 18$

$72^{2} - 18^{2} = (72 + 18) (72 - 18)$

$= 90 \times 54$

$= 4860$

Suggest Corrections

Similar questions

Find the value using identities : $182 \times 182 - 2 \times 182 \times 62 + 62 \times 62$

(82)^{2} - (18)^{2}

(128)^{2} - (72)^{2}

197 \times 203

\frac{198 \times 198 - 102 \times 102}{96}

(14.5 \times 15.3)

(8.63)^{2} - (1.37)^{2}

204 \times 206

992^{2}

(4.5)^{2}

102^{3}

Join BYJU'S Learning Program