Question

Using information given in the figure, calculate the value of x and y.

Answer 1

In $△ABC$

$\angle ACD=\angle CAB+\angle ABC$ (Exterior angle of triangle is equal to sum of interior opposite angles )

$x={34}^{\circ }+{62}^{\circ }$

$x={96}^{\circ }$

In $△DEC$

$\angle DEA=\angle EDC+\angle DCE$ (Exterior angle of triangle is equal to sum of interior opposite angles)

$y={24}^{\circ }+{96}^{\circ }$

$x={120}^{\circ }$