Question

Using Kirchhoff's rules to determine the value of the current $I_1$ flowing in the circuit shown in figure

Answer 1

Using Kirchhoff's voltage law in the above loop:

$-20V+I_1\times 20+I_1\times 30=0$

$50I_1=20$

$I_1=\frac{20}{50}=\frac{2}{5}=0.4A$