Question

Using KVL and KCL find the branch currents in the given circuit.

Answer 1

Mesh 1:-$2I_1+2(I_1+I_2)=6v$

$⟹4I_1-2I_2=6v$

$⟹2I_1-I_2=3\to \left(1\right)$

Mesh 2:-$4I_2+2(I_1+I_2)=2v$

$⟹6I_2-2I_1=2\to \left(2\right)$

Equating $\left(2\right)$ and $\left(1\right)$

$I_2=1A$

$I_1=2A$