Using prime factorisation find HCF of 64, 96, and 216

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Solution

Given us : 64, 96 and 216
by prime factorisation of
64= 2 x 2 x 2 x 2 x 2 x 2
96 = 2 × 2 × 2 × 2 × 2 × 3
216= 2 × 2 × 2 × 3 × 3 × 3
Here, common factors 2 x 2 x 2 = 8
Hence, HCF of (64, 96 and 216) is 8

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Using prime factorisation find HCF of 64, 96, and 216

Given us : 64, 96 and 216by prime factorisation of 64= 2 x 2 x 2 x 2 x 2 x 296 = 2 × 2 × 2 × 2 × 2 × 3216= 2 × 2 × 2 × 3 × 3 × 3Here, common factors 2 x 2 x 2 = 8Hence, HCF of (64, 96 and 216) is 8

Given us : 64, 96 and 216
by prime factorisation of
64= 2 x 2 x 2 x 2 x 2 x 2
96 = 2 × 2 × 2 × 2 × 2 × 3
216= 2 × 2 × 2 × 3 × 3 × 3
Here, common factors 2 x 2 x 2 = 8
Hence, HCF of (64, 96 and 216) is 8