Using quadratic formula find the roots of quadratic equation $2 x^{2} - 3 x + 1 = 0$

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Solution

$2 x^{2} - 3 x + 1 = 0$

Here, $a = 2, b = - 3, c = 1$

Using the quadratic formula, we have

$x = \frac{- b \pm \sqrt{b - 4 a c}}{2 a}$

$\Rightarrow x = \frac{- (- 3) \pm \sqrt{{(- 3)}^{2} - 4 \cdot 2 \cdot 1}}{2 \times 2}$

$\Rightarrow x = \frac{3 \pm \sqrt{9 - 8}}{4}$

$\Rightarrow x = \frac{3 \pm 1}{4}$

$\Rightarrow x = \frac{3 + 1}{4} = 1$ OR $x = \frac{3 - 1}{4} = \frac{1}{2}$

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