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Question

Using quadratic formula solve the           abx²+(b²-ac)xv- bc =o for x


Solution

Consider, abx2 +(b2-ac)x-bc = 0
⇒ abx2 + b2x – acx – bc = 0
⇒ bx (ax + b) – c(ax + b) = 0
⇒ (ax + b)(bx – c) = 0
(ax+b)=0
ax=-b
x=-b/a
(bx-c)=0
bx=c
x=c/b
so roots are -b/a;c/b

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