Using suitable rearrangement- find the sum-4-7 - -4-9 - 3-7 - -13-9

Here, ⇒4/7 + ( 4/9 ) + 3/7 + ( 13/9 ) = 4/7 + 3/7 + ( 4/9 ) + ( 13/9 ) nbsp; nbsp; nbsp;[Using commutative property] = 7/7 17/9 =1 17/9 = ...

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Using suitabl...

Question

Using suitable rearrangement, find the sum.
$\frac{4}{7} + (\frac{- 4}{9}) + \frac{3}{7} + (\frac{- 13}{9})$

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Solution

Here,

$\Rightarrow \frac{4}{7} + (\frac{- 4}{9}) + \frac{3}{7} + (\frac{- 13}{9})$

$= \frac{4}{7} + \frac{3}{7} + (\frac{- 4}{9}) + (\frac{- 13}{9})$ [Using commutative property]

$= \frac{7}{7} - \frac{17}{9}$

$= 1 - \frac{17}{9}$

$= \frac{9 - 17}{9}$

$= \frac{- 8}{9}$

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Similar questions

Re-arrange suitably and find the sum in each of the following :

(i) $\frac{11}{12} + \frac{- 17}{3} + \frac{11}{2} + \frac{- 25}{2}$

(ii) $\frac{- 6}{7} + \frac{- 5}{6} + \frac{- 4}{9} + \frac{- 15}{7}$

(iii) $\frac{3}{5} + \frac{7}{3} + \frac{9}{5} + \frac{- 13}{15} + \frac{- 7}{3}$

(iv) $\frac{4}{13} + \frac{- 5}{8} + \frac{- 8}{13} + \frac{9}{13}$

(v) $\frac{2}{3} + \frac{- 4}{5} + \frac{1}{3} + \frac{2}{5}$

(vi) $\frac{1}{8} + \frac{5}{12} + \frac{2}{7} + \frac{7}{12} + \frac{9}{7} + \frac{- 5}{16}$

$(i) \frac{3}{7} + \frac{- 4}{9} - \frac{- 11}{7} - \frac{7}{9} (i i) \frac{2}{3} + \frac{- 4}{5} - \frac{1}{3} - \frac{2}{5} (i i i) \frac{4}{7} - \frac{- 8}{9} - \frac{- 13}{7} + \frac{17}{9}$

Q. Using suitable rearrangement, find the sum.

\frac{4}{7} + (\frac{- 4}{9}) + \frac{3}{7} + (\frac{- 13}{9})

Q. Question 102(i)
Using suitable rearrangement, find the sum.

\frac{4}{7} + (\frac{- 4}{9}) + \frac{3}{7} + (\frac{- 13}{9})

Using suitable rearrangement, find the sum of the following:
$\frac{4}{7} + (-\frac{4}{9})+\frac{3}{7}+(-\frac{13}{9})$

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Using suitable rearrangement, find the sum. 47+(−49)+37+(−139)

Here, ⇒47+(−49)+37+(−139) =47+37+(−49)+(−139) [Using commutative property] =77−179 =1−179 =9−179 =−89

Using suitable rearrangement, find the sum.
$\frac{4}{7} + (\frac{- 4}{9}) + \frac{3}{7} + (\frac{- 13}{9})$

Here,

$\Rightarrow \frac{4}{7} + (\frac{- 4}{9}) + \frac{3}{7} + (\frac{- 13}{9})$

$= \frac{4}{7} + \frac{3}{7} + (\frac{- 4}{9}) + (\frac{- 13}{9})$ [Using commutative property]

$= \frac{7}{7} - \frac{17}{9}$

$= 1 - \frac{17}{9}$

$= \frac{9 - 17}{9}$

$= \frac{- 8}{9}$