Question

Using the common factor method, find the H.C.F. of
(iv) $8,12\text{and}18$

Answer 1

(iv) Factor of a number: The number by which the given number can be divided completely.
Factors of $8=1,2,4,8$
Factors of $12=1,2,3,4,6,12$
Factors of $18=1,2,3,6,9,18$
$\therefore$ Common factors between $8,12$ and $18=1,2$
Hence, H.C.F. of 8, 12 and 18 is 2.