Question

Using the common factor method, find the H.C.F. of
(v) $24,36,45\text{and}60$

Answer 1

(v) Factor of a number: The number by which the given number can be divided completely.
Factors of $24=1,2,3,4,6,8,12,24$
Factors of $36=1,2,3,4,6,9,12,18,36$
Factors of $45=1,3,5,9,15,45$
Factors of $60=1,2,3,4,5,6,10,12,15,20,30,60$
$\therefore$ Common factors between $24,36,45$ and $60=1,3$
Hence, H.C.F. of 24, 36, 45 and 60 is 3.