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Byju's Answer
Standard XII
Mathematics
Multiplication of Matrices
Using the fac...
Question
Using the factor theorem it is found that a + b, b + c and c + a are three factors of the determinant
-
2
a
a
+
b
a
+
c
b
+
a
-
2
b
b
+
c
c
+
a
c
+
b
-
2
c
The other factor in the value of the determinant is
(a) 4
(b) 2
(c) a + b + c
(d) none of these
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Solution
(a) 4
Δ
=
-
2
a
a
+
b
a
+
c
b
+
a
-
2
b
b
+
c
c
+
a
c
+
b
-
2
c
Let
a
+
b
=
2
C
,
b
+
c
=
2
A
and
c
+
a
=
2
B
.
⇒
a
+
b
+
b
+
c
+
c
+
a
=
2
A
+
2
B
+
2
C
⇒
2
a
+
b
+
c
=
2
A
+
B
+
C
⇒
a
+
b
+
c
=
A
+
B
+
C
Also
,
a
=
a
+
b
+
c
-
b
+
c
=
A
+
B
+
C
-
2
A
=
B
+
C
-
A
Similarly
,
b
=
C
+
A
-
B
,
c
=
A
+
B
-
C
Δ
=
2
A
-
2
B
-
2
C
2
C
2
B
2
C
2
B
-
2
C
-
2
A
2
A
2
B
2
A
2
C
-
2
A
-
2
B
=
8
×
A
-
B
-
C
C
B
C
B
-
C
-
A
A
B
A
C
-
A
-
B
taking
out
2
common
from
R
1
R
2
R
3
=
8
×
A
-
B
C
+
B
B
B
-
A
B
-
C
A
B
+
A
C
-
B
C
-
A
-
B
Applying
C
1
→
C
1
+
C
2
,
C
2
→
C
2
+
C
3
=
8
×
A
-
B
C
+
B
B
0
2
B
A
+
B
2
B
0
C
-
B
Applying
R
2
→
R
1
+
R
2
,
R
3
→
R
2
+
R
3
=
8
×
A
-
B
2
B
A
+
B
0
C
-
B
+
2
B
×
C
+
B
B
2
B
A
+
B
Expanding
along
C
1
=
16
B
A
-
B
C
-
B
+
C
+
B
A
+
B
-
2
B
2
=
32
ABC
=
32
b
+
c
2
c
+
a
2
a
+
b
2
=
4
a
+
b
b
+
c
c
+
a
Hence
,
4
is
the
other
factor
of
the
determinant
.
Suggest Corrections
0
Similar questions
Q.
Using the factor theorem it is found that
b
+
c
,
c
+
a
and
a
+
b
are three factors of the determinant
∣
∣ ∣
∣
−
2
a
a
+
b
a
+
c
b
+
a
−
2
b
b
+
c
c
+
a
c
+
b
−
2
c
∣
∣ ∣
∣
.
The other factor in the value of the determinant is
Q.
∣
∣ ∣
∣
−
2
a
a
+
b
a
+
c
b
+
a
−
2
b
b
+
c
c
+
a
c
+
b
−
2
c
∣
∣ ∣
∣
=
4
(
b
+
c
)
(
c
+
a
)
(
a
+
b
)
.
Q.
Solve
∣
∣ ∣
∣
−
2
a
a
+
b
a
+
c
a
+
b
−
2
b
b
+
c
c
+
a
c
+
b
−
2
c
∣
∣ ∣
∣
=
4
(
a
+
b
)
(
b
+
c
)
(
c
+
a
)
.
Q.
If a, b, c are real numbers, then the value of the determinant
∣
∣ ∣
∣
1
−
a
a
−
b
−
c
b
+
c
1
−
b
b
−
c
−
a
c
+
a
1
−
c
c
−
a
−
b
a
+
b
∣
∣ ∣
∣
is
Q.
∣
∣ ∣
∣
−
2
a
a
+
b
a
+
c
b
+
a
−
2
a
b
+
c
c
+
a
c
+
b
−
c
∣
∣ ∣
∣
=
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