Question 90 (v)

Factorise the following, using the identity, $a^{2} - 2 a b + b^{2} = (a - b)^{2}$ .

$4 a^{2} - 4 a b + b^{2}$

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Solution

We have,
$4 a^{2} - 4 a b + b^{2} = (2 a)^{2} - 2.2 a . b + b^{2} = (2 a - b)^{2} = (2 a - b) (2 a - b)$

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Question 92 (v)

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