Question 89 (v)

Factorise the following, using the identity, $a^{2} + 2 a b + b^{2} = (a + b)^{2}$

$4 x^{2} + 4 x + 1$

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Solution

We have, $4 x^{2} + 4 x + 1$
$(2 x)^{2} + 2.2 x .1 + 1^{=} (2 x + 1)^{2} = (2 x + 1) (2 x + 1)$

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