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Fundamental Theorem of Arithmetic

V is product ...

Question

V is product of first 41 natural numbers. A = V+1. The number of primes among A+1, A+2, A+3, A+4 ............... A+39, A+40 is:

(A) 1 (B) 2

(C) 3 (D) 0

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Solution

D) 0
The product of first 41 natural numbers=41!

numbers=41!+1, 41!+2, 41!+3.....

they all will have one number in common so eg: (41!+3) will have 3 common.......can we written as 3(41!/3 +1)

similarly the others too.

so 0

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