Question

Question 2(v)
Write the additive inverse of each of the following:
$\frac{19}{-6}$

Answer 1

We know that additive inverse of a rational number
$\frac{a}{b}is\left(\frac{-a}{b}\right),suchthat\frac{a}{b}+\left(\frac{-a}{b}\right)=0$
Additive inverse of
$\frac{19}{-6}$ is $\frac{19}{6}$.