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Bond Order and Enthalpy

Valence shell...

Question

Valence shell electronic configuration of ion of $N_{2}$ molecule is written as $(σ 2 s)^{2} (σ^{} 2 s)^{2} (Π 2 p)^{4} (σ 2 p)^{2} (Π^{} 2 p)^{1}$ . Hence the bond order of Nitrogen molecular ion is:-

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Solution

Bond order (B.O)= $\frac{(n o . o f e^{-} i n b o n d i n g o r b i t a l s) - (n o . o f e^{-} i n a n t i - b o n d i n g o r b i t a l s)}{2}$
= $\frac{(2 + 4 + 2) - (2 + 1)}{2}$
= $\frac{8 - 3}{2}$
= $\frac{5}{2}$
Bond Order (B.O) $= 2.5$

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