Value of 1 - 131 - 1321 - 1341 - 138- - - 1 - 132n is equal to

The correct option is A 32(1 (13)^2n+1) ...

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Complex Numbers

Value of 1 ...

Question

Value of $(1 + \frac{1}{3}) (1 + \frac{1}{3^{2}}) (1 + \frac{1}{3^{4}}) (1 + \frac{1}{3^{8}}) . . . (1 + \frac{1}{3^{2 n}})$ is equal to

\frac{3}{2} (1 - (\frac{1}{3})^{2 n + 1})

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\frac{3}{2} (1 - (\frac{1}{3})^{2 n})

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\frac{3}{2} (1 - (\frac{1}{3})^{2 n - 1})

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None of these

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Similar questions

Find the value of $^{n} C_{0}$ + $^{n} C_{3}$ + $^{n} C_{6}$ _{............................}

$\frac{{(243)}^{\frac{n}{5}} \times 3^{2 n + 1}}{9^{n} \times 3^{n - 1}} = ?$

\frac{1}{3.5} + \frac{1}{5.7} + \frac{1}{7.9} + . . . . . . . . . . . . . . + \frac{1}{(2 n + 1) (2 n + 3)} = \frac{n}{3 (2 n + 3)}

$\frac{1}{3.5} + \frac{1}{5.7} + \frac{1}{7.9} + . . . . . . + \frac{1}{(2 n + 1) (2 n + 3)} = \frac{n}{3 (2 n + 3)}$

\frac{1}{3.5} + \frac{1}{5.7} + \frac{1}{7.9} + . . . + \frac{1}{(2 n + 1) (2 n + 3)} = \frac{n}{3 (2 n + 3)}

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