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B
0.987calmol−1K−1
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C
8.3Jmol−1K−1
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D
83ergmol−1K−1
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Solution
The correct option is C8.3Jmol−1K−1 Units of R (i)in lit atm⇒0.082L atmmol−1k−1 (ii) in calories⇒1.987calmol−1k−1 (iii)in M.K.S. system⇒8.314 Jmol−1k−1 (iv) C.G.S. system⇒8.314×107ergmol−1k−1