wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Value of 10(1+x+x2+x3)(1+3x+5x2+7x3)dx is

Open in App
Solution

We have,
10(1+x+x2+x3)(1+3x+5x2+7x3)dx
Let x=t2dx=2t dt
I=210(t+t3+t5+t7)(1+3t2+5t4+7t6)dt
Let (t+t3+t5+t7)=u(1+3t2+5t4+7t6) dt=du
=240u.du=(u2)40=16

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Fundamental Theorem of Calculus
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon