Value of $[({log}_{b} a) ({log}_{c} b) ({log}_{a} c)]$

0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

a b c

No worries! We‘ve got your back. Try BYJU‘S free classes today!

log a b c

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $1$
$({log}_{b} a) ({log}_{c} b) ({log}_{a} c) = \frac{{log}_{p} a}{{log}_{p} b} \times \frac{{log}_{p} b}{{log}_{p} c} \times \frac{{log}_{p} c}{{log}_{p} a} = \frac{{log}_{p} a b c}{{log}_{p} a b c} = 1$

Suggest Corrections

Similar questions

[l o g_{b} a l o g_{c} a - l o g_{a} a] + [l o g_{a} b l o g_{c} b - l o g_{b} b] + [l o g_{a} c l o g_{b} c - l o g_{c} c] = 0

[l o g_{b} a l o g_{c} a - l o g_{a} a] + [l o g_{a} b l o g_{c} b - l o g_{b} b] + [l o g_{a} c l o g_{b} c - l o g_{c} c] = 0, t h e n a b c =

\frac{l o g a}{b - c} = \frac{l o g b}{c - a} = \frac{l o g c}{a - b}

a^{a} . b^{b} . c^{c}

a, b, c \in + R

a^{log b - log c} + b^{log c - log a} + c^{log a - log b}

If a, b, c are in G.P., prove that log a, log b, log c are in A.P.

Join BYJU'S Learning Program