Value(s) of m for which system remains at rest (pulleys and strings are ideal) [g=10m/s2]:
A
1kg
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B
2kg
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C
18kg
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D
20kg
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Solution
The correct options are A2kg C18kg fmax=20×0.4×10=80N For equilibrium minimum value of m⇒m(10)=100−80⇒m=2kg maximum value of m⇒m(10)=100+80⇒m=18kg So, (B) and (C) are correct.