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Byju's Answer
Standard XII
Chemistry
Real Gases
Van der Waals...
Question
Van der Waals equation at high pressure for 1 mole is?
A
P
V
+
a
V
=
R
T
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B
PV = RT
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C
P (V + b ) = RT
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D
P (V - b ) = RT
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Solution
The correct option is
D
P (V - b ) = RT
Given
n
=
1
At high pressure
a
V
2
is neglected when compared to
P
.
Hence the equation
(
P
+
a
V
2
)
(
V
−
b
)
=
R
T
reduces to
P
(
V
−
b
)
=
R
T
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Similar questions
Q.
Using Van der Waals equation,
[
P
+
a
V
2
]
(
V
−
b
)
=
R
T
, a
t high pressure, the Van der Waals equation gets reduced to :
Q.
Match the van der Waal's equation for one mole of gas given in column B to the conditions given in column A.
Column A
Column B
(A) High pressure
(i)
P
V
=
R
T
+
P
b
(B) Low pressure
(ii)
P
V
=
R
T
−
a
V
(C)
P
→
0
(iii)
P
V
=
R
T
(D) Neither
a
nor
b
is negligible
(iv)
(
P
+
a
V
2
)
(
V
−
b
)
=
R
T
Q.
At low pressures (For 1 mole), the van der Waals equation is written as
[
p
+
a
V
2
]
V
=
R
T
The compressibility factor is then equal to:
Q.
Using Van der Waals equation
[
P
+
a
V
2
]
(
V
−
b
)
=
R
T
, t
he term that accounts for effective volume in the Van der Waals equation for non-ideal gas is :
Q.
Using Van der Waals equation
[
P
+
a
V
2
]
(
V
−
b
)
=
R
T
, t
he term that accounts for intermolecular forces in the Van der Waals equation for non-ideal gas is______
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