Van't Hoff factor of a mixture of two moles of KI with 1 mole $H g I_{2}$ in a solution of water is :

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Solution

Two moles of KI react with on mole of $H g I_{2}$ to form one mole of the complex $K_{2} [H g I_{4}]$ .
$2 K I + H g I_{2} ⇌ K_{2} [H g I_{4}]$
In aqueous solution, one mole of the complex $K_{2} [H g I_{4}]$ dissociates to give 3 moles of ions.
$K_{2} H g I_{4} ⇌ 2 K^{+} + [H g I_{4}]^{2 -}$
Van't Hoff factor $i = \frac{n (o b s e r v e d)}{n (t h e o r e t i c a l)} = \frac{3}{1} = 3$
Thus, Van't Hoff factor of a mixture of two moles of KI with 1 mole $H g I_{2}$ in a solution of water is 3.

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