Van't Hoff factor of $H g_{2} C l_{2}$ in its aqueous solution will be ( $H g_{2} C l_{2}$ is $80 %$ ionized in the solution):

1.6

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2.6

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3.6

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4.6

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Solution

The correct option is B $2.6$
$H g_{2} C l_{2} ⇌ H g_{2}^{2 +} + 2 C l^{-}$

Here, $n = 3$

Now,
$α = \frac{i - 1}{n - 1}$

$0.8 = \frac{i - 1}{3 - 1}$

$i = 2.6$

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