Question

Van’t Hoff factor of $H{g}_{2}C{l}_2$ in its aqueous solution will be $(H{g}_{2}C{l}_2$ is 80% ionized is the solution)

• A. 1.6
• B. 2.6
• C. 3.6
• D. 4.6

Answer 1

The correct option is B 2.6

$$\begin{array}{ccccc}H{g}_{2}c{l}_2& \rightleftharpoons & H{g}_2^{2+}& +& 2c{l}^{-}\\ 1& & 0& & 0\\ 1-08& & 0.8& & 1.6\end{array}$$
$i=\frac{0.2+0.8+1.6}{1}$
i =2.6