Vapour density of an organic compound is 23. It contains 52.17% of carbon and 13% of hydrogen. The compound gives iodoform test. The compound is :

ethanol

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dimethyl ether

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acetone

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methanol

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Solution

The correct option is B ethanol
Carbon ; number of moles = $\frac{52.17}{12} = 4.34$
Hydrogen ; number of moles = $\frac{13}{1} = 13$
Oxygen ; number of moles = $\frac{34. 83}{16} = 2.17$
Relative ratios ; Carbon : $\frac{4.34}{2.17} = 2$
Hydrogen : $\frac{13}{12.7} = 6$
Oxygen : $\frac{2.17}{2.17} = 1$
Empirical formula is $C_{2} H_{6} O$ .

The molar mass = 2 $\times$ vapour density
=2 $\times$ 23 = 46

The compound is $C_{2} H_{5} O H$

That is ethanol since it gives positive iodoform test.

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