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Question

# Vapour density of PCl5 is 104.16 but when heated at 230o C its vapour density is reduced to 62. The degree of dissociation of PCl5 at this temperature will be:

A
6.8%
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B
68%
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C
46%
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D
60%
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Solution

## The correct option is D 68% PCl5↔PCl3+Cl2 Initial C 0 0 At eq.C(1−α) Cα Cα Total moles at equilibrium =C(1−α)+Cα+Cα=C(1+α) For a reaction at equilibrium, Vapour density is inversely proportional to the number of moles. Therefore,Totalmoles of eq.initial total moles=vapour density initialvapour density ateq. C(1+α)C=Dd 1+α=Dd α=Dd−1 D=104.16 d=62 ∴α=104.1616−1=0.68 ∴, α=68 %

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