wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Vapour density of PCl5 is 104.16 but when heated to 230C its vapour density is reduced to 62.

The degree dissociation of PCl5 at this temperature will be:

A
0.68%
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
68%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
46%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
64%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

PCl5PCl3+PCl2


PCl5 ⇌  PCl3 + Cl2PCl_5\, \rightleftharpoons\, PCl_3\, +\, Cl

Initial aaa 0 0
Final a−axa-axaaxaxaxax axaxax
i=aax+ax+axa=1+x

i=normalvapourdensityabnormalvapourdensity=104.1662=1.68

i=a−ax+ax+axa=1+xi=\dfrac{a-ax+ax+ax}{a}=1+x

⇒1+x=1.68\Rightarrow 1+x=1.681+x=1.68

⇒x=0.68\Rightarrow x=0.68x=0.68


The degree of dissociation of PCl5 is 68%

Conclusion: The correct option is (D) 68%


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relative Lowering of Vapour Pressure
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon