Vapour pressure of pure benzene and toluene at 313K is 150 and 50 mmHg respectively. Calculate the vapour pressure of the mixture containing equal masses of benzene and toluene at 313K.

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Benzene and toluene form nearly ideal solution .At 313K the vapour pressure of pure benzene is 150mm Hg and of pure toluene is 50 mm Hg .calculate vapour pressure of mixture of these two containing their equal masses at 313 K .

Q. Benzene and toluene from two ideal solution A and B at 313 K. Solution A (total pressure

P_{A}

) contains equal mole of toluene and benzene. Solution B contains equal masses of both A (total pressure

P_{B}

). The vapour pressure of benzene and toluene are 160 and 60 mm Hg respectively at 313 K. Calculate the value of

P_{A} + P_{B}

(Round-off the answer).

Q. A cylinder contains

0.9

moles of benzene vapour and

0.1

moles of toluene vapour at

50^{o} C

. The pure vapour pressure of benzene liquid and the pure vapour pressure of toluene liquid at

50^{o}

C are 600 torr and 200 torr respectively.
What is the mole fraction of liquid benzene in the solution?

Q. A cylinder contains

0.9

moles of benzene vapour and

0.1

moles of toluene vapour at

50^{o} C

. The pure vapour pressure of benzene liquid and the pure vapour pressure of toluene liquid at

50^{o}

C are 600 torr and 200 torr respectively.
What is the mole fraction of liquid benzene in the solution?

Q. The vapour pressure of pure benzene at

88^{o} C

is 957 mm and that of toluene at the same temperature is 379.5 mm. Calculate the composition of benzene-toluene mixture boiling at

88^{o} C

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