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Byju's Answer
Standard XII
Physics
Vector Component
A =2 î+3 ĵ+k̂...
Question
→
A
=
2
^
i
+
3
^
j
+
^
k
and
→
=
4
^
i
+
3
^
j
. Magnitude of the component of vector
→
A
along vector
→
B
is
.
Open in App
Solution
→
A
.
→
B
=
A
B
c
o
s
θ
A
c
o
s
θ
=
→
A
.
→
B
B
A
c
o
s
θ
=
(
2
^
i
+
3
^
j
+
^
k
)
.
(
4
^
i
+
3
^
j
)
5
=
3.4
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→
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