wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A=2^i+3^j+^k and =4^i+3^j. Magnitude of the component of vector A along vector B is .

Open in App
Solution


A.B=AB cos θ
A cosθ=A.BB
A cosθ=(2^i+3^j+^k).(4^i+3^j)5=3.4

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Vector Components
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon